(X+Y)(X-Y) – X&#39Y&#39+Xy+X&#39Y

JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.

You are watching: (x+y)(x-y)

Hi, According to wolfram alpha x+y / x-y can also be represented as <-(2x)/(y-x)> -1When it is in this form it works for me I just can”t seem to get it in that form,any help (or suggestions or basic rules to apply) would be greatly appreciated.
Sorry I just realised this is in the wrong section, it is for a limit question but the question itself is not. (I don”t know how to move this into the right section)
We want to express the express (x+y)/(x-y) as < -2x / (y-x) > – 1.In order to form it into that form we will first take out -1 common from the denominator to get(x+y)/(x-y) = – ( x+y)/ (y-x) . Now divide the numerator by the denominator, quotient being 1 and remainder 2x. Thus we get: (x+y)/(x-y) = – ( x+y)/ (y-x) = – < 1 + 2x / ( y-x) > = -1 – 2x / ( y-x)

*

Reactions:1 person
Thank you for the quick reply, but I have no idea how you get from:”Now divide the numerator by the denominator, quotient being 1 and remainder 2x. Thus we get: – ( x+y)/ (y-x) = – < 1 + 2x / ( y-x) > = -1 – 2x / ( y-x)”I haven”t done algebra in 4-5 years, could you please explain this step by step? (as I have forgotten “basic math rules”)It”s – ( x+y)/ (y-x) = – < 1 + 2x / ( y-x) > that I don”t understand.

*

See more: Orlando To Seattle Flight – Cheap Flights From Orlando To Seattle

Sorry I just realised this is in the wrong section, it is for a limit question but the question itself is not. (I don”t know how to move this into the right section)
According to Wolfram Alpha: (displaystyle frac{x+y}{x-y}) can also be written (displaystyle frac{-2x}{y-x}-1)
Their answer is correct . . . but really stupid!I tried to figure out their reasoning . . . weird!We have: .(displaystyle frac{x+y}{x-y})Multiply by (displaystyle frac{-1}{-1}!:;;frac{-1}{-1}cdotfrac{x+y}{x-y} ;=;frac{-x-y}{-x+y} ;=;frac{-y-x}{y-x})Long division:. . (displaystyle egin{array}{ccccc}&&&-1 \ && — & — \ y-x & | & -y & -x \ && -y & +x \ && — & — \ &&& -2xend{array})Therefore: .(displaystyle frac{-y-x}{y-x} ;=;-1 – frac{2x}{y-x})~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~Why not divide “normally”? .(displaystyle frac{x+y}{x-y}). . (displaystyle egin{array}{cccccc} &&&&1 \ && –&–&– \ x-y & | & x & + & y \ && x & -& y \ && –&–&– \ &&&& 2y end{array})Therefore: .(displaystyle frac{x+y}{x-y} ;=;1 + frac{2y}{x-y})

Similar Math DiscussionsMath ForumDate
How to simplify this expression – with exponents? Please help! Algebra Mar 11, 2016
Help please simplifying this equation to be graphed Math Puzzles Dec 15, 2015
Please help to simplify the algebraic expression Algebra Mar 17, 2014
Simplifying Question — Please Help? Algebra Jan 13, 2013

Similar threads
How to simplify this expression – with exponents? Please help!
Help please simplifying this equation to be graphed
Please help to simplify the algebraic expression
Simplifying Question — Please Help?

See more: Spiritual Meaning Of Body Parts, All About Heaven

Math Help Forum

Mathematics is concerned with numbers, data, quantity, structure, space, models, and change. Founded in 2005, Math Help Forum is dedicated to free math help and math discussions, and our math community welcomes students, teachers, educators, professors, mathematicians, engineers, and scientists.

Published

Leave a comment

Your email address will not be published. Required fields are marked *