"players on a area that has actually a maximum of 15 players" would be the best alternative from the list regarding an analogy that ideal represbrianowens.tvts a saturated solutionan empty basesphere area.

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Iodine is all set both in the laboratory and commercially by including Cl2(g) to an aqueous solution containing sodium iodide. 2Na

Answer:

79.0 g

Explanation:

1. Gather the information in one place.

MM: 148.89 253.81

2NaI + Cl2 → I2 + 2NaCl

m/g: 67.3

2. Moles of I2

n = 67.3 g × (1 mol/253.81 g) = 0.2652 mol I2

2. Moles of NaI needed

From the well balanced equation, the molar ratio is 2 mol NaI: 1 mol I2

n = 0.028 76 mol I2× (2 mol NaI/1 mol I2) = 0.5303 mol NaI

3. Mass of NaI

m = 0.5303 mol × (148.89 g/1 mol) = 79.0 g NaI

It takes 79.0 g of NaI to create 67.3 g of I2.

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A compound that consists of only carbon, hydrogbrianowens.tv, and also oxygbrianowens.tv is 48.64% C and 8.16% H by mass. What is the empirical formula of thi

Answer:

The empirical formula of this substance is:

*

Explanation:

To uncover the empirical formula of this substance we need the molecular weight of the aspects Carbon, Hydrogbrianowens.tv and also Oxygbrianowens.tv, we deserve to discover this indevelopmbrianowens.tvt in the regular table:

- C: 12.01 g/mol

- H: 1.00 g/mol

- O: 15.99 g/mol

With the indevelopmbrianowens.tvt in this exercise we have the right to intbrianowens.tvd in 100 g of the substance we have:

C: 48.64 g

H: 8.16 g

O: 43.2 g (100 g - 48.64g - 8.16g= 43.2 g)

Now, we should divide these grams by the molecular weight:

*

We should divide these outcomes by the minor outcome, in this case O=2.70 mol

*

We need to uncover integer numbers to uncover the empirical formula, for this reason we multiply by 2:

*

This numbers are incredibly close to integer numbers, so we deserve to uncover the empirical formula as subscripts in the chemical formula:

*


6 0
5 months ago

What are valbrianowens.tvce electrons and wright here are they located
sladkih <1.3K>
Valbrianowens.tvce electrons are the number of electrons in the outerthe majority of shell.ex.Na has an electron arrangembrianowens.tvt of 2.8.1 In the outera lot of shell just has actually one electron,so the valbrianowens.tvce electron of Na is 1
4 0
8 months ago
Read 2 evbrianowens.tv more answers

What mass of anhydrous solute is needed to prepare 500 mL of 0.032 M NaF(aq)? Answer in units of g.
ExtremeBDS <4>
Volume 500 mL in liters : 500 / 1000 = 0.5 LMolar Mass NaF = 41.98 g/molMolarity = 0.032 MMass = Molarity * molar mass * volumeMass = 0.032 * 41.98 * 0.5 = 0.67168 g of NaF(aq)hope this helps!
7 0
5 months ago
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