# What Is The Work Ww Done On The Box By The Weight Of The Box?

6) . The normal force acting on the box has a magnitude n=1.7N, the coefficient of kinetic friction between the box and the plane is μk=0.30, and the displacement d⃗ of the box is 1.8 m down the inclined plane. . . I got Part A, need help with B and C . .

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What is the work Ww done on the box by the weight of the box? . Express your brianowens.tvs in joules to two significant figures. . . W=1.8J . . B)What is the work Wn done on the box by the normal force? .

The work done on the box by the weight of the box is 1.8 Joule

The work done on the box by the normal force is 0 Joule

The work done on the box by the force of kinetic friction is -0.918 Joule

### Further explanation

Let”s recall Kinetic Energy Formula as follows:

Ek = Kinetic Energy ( Joule )

m = mass of the object ( kg )

v = speed of the object ( m/s )

Let us now tackle the problem !

Given:

weight of the box = w = 2.0 N

angle of inclined plane = θ = 30°

normal force = N = 1.7 N

coefficient of kinetic friction = μ = 0.30

displacement of the box = d = 1.8 m

work done by weight = W_w = ?

work done by normal force = W_n = ?

work done by the force of kinetic friction = W_f = ?

Solution:

We could calculate work done by weight as follows:

Because the direction of displacement is perpendicular to the direction of normal force , then:

Finally, we could calculate the work done by friction as follows: