The pressure in the loop is obtained by summing up the forces developed by the 2 parallel wires in the loop.

You are watching: What is the magnitude, f, of the net force on the loop?

The force on the left side of the loop is provided by:

F1=μ0i1i22πr=μ0i1i2a2π(d-a2)

Force ~ above the ideal side that the loop:

F2=μ0i1i22πr=μ0i1i2a2π(d+a2)


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A square loop the wire v side lengtha tote a current I1. The center of the loop is situated a distance d from an infinite wire transferring a present I2. The limitless wire and also loop room in the exact same plane; 2 sides that the square loop room parallel to the wire and also two are perpendicular as shown.

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Part A.What is the magnitude, F, the the net force on the loop? refer the force in regards to I1, I2, a, d, and μ0.

Part B.The magnetic moment m→of a present loop is characterized as the vector who magnitude amounts to the area that the loop time the magnitude of the existing flowing in the (m = IA), and whose direction is perpendicular to the plane in which the existing flows. Discover the magnitude, F, the the force,F, of the pressure on the loop from component A in terms of the magnitude of that is magnetic moment. Express F in terms of m, I2, a, d, and also μ0.


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