E=kqr2, where k is the Coulomb constant, r is the distance of the charge, and E is the electric field.
From the given information, the distance of charge q1 from the origin is given by:
r1 = sqrt(0.6002 + 0.8002) =1.0 m
The distance of q2 from the origin:
r2 = sqrt(0.6002 + 02) =0.600 m
E1 = kq/r12 = (9.0 × 109)(4.00 × 10-9)/1.02= 36.0 N/C
E2 = (9.0 × 109)(6.00 × 10-9)/0.6002= 150 N/C
Calculate the x and y components of the electric field at the origin due to the two charges.
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A point charge q1 = -4.00 nC is at the point x = 0.600 meters, y = 0.800 meters, and a second point charge q2 = +6.00 nC is at the point x = 0.600 meters, y = 0.
A) Calculate the magnitude E of the net electric field at the origin due to these two point charges.
B) What is the direction, relative to the negative x-axis, of the net electric field at the origin due to these two point charges.
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